Hehe Nope, no source hacking. It makes much more sense now...
If anyone is wondering, boB from Midnite explained how the register is encoded...
4372 is the WBJR temp register, and the "47" in the (0xXX47) hex output is the encoded temperature in deg C.
After masking off the high 8 bits and obtaining the 47, convert it to decimal.
0x47 = 71
Subtract 50 from this result to obtain deg C, 21 in this case.