do you think it would work if i removed that resistor, soldered 2 wires onto the pads then soldered them to a socket glued to the top of the board, so that i can easily change the resistors without pulling too much apart?
If you think about the way a CT works, you can deduce it will be fine, within reason.
A CT has a primary (usually a single turn), and a secondary - of some number of turns. Lets say it's 1000 turns.
For 10 amps through the primary, there will be 10/1000 amps in the secondary.
With no current, the voltage across the output will skyrocket (which is why you NEVER open-circuit the secondary of a CT!)
The burden resistor (load, or shunt, if you like) across the output of the CT determines the voltage across it, for a given current. So in the example above, 10A in a 1000:1 CT, means 10/1000 = 1/100A = 10mA
With a 1K resistor, you should see 10V. With a 100R resistor, you should see 1V
If the load resistor is very low value, then connection resistance will be an issue, but for any "sane" value of R, the connection resistance from your connector will be negligible.